画像をダウンロード plot x2 (y-^x)2=1 nima 795243-Plot x : 1 x : 2

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 Usually you plot complex number in standard coordinate plane using vertical axis as the imaginary part axis So to plot −2 −i you just plot point ( − 2, − 1) graph { ( (x2)^2 (y1)^01)=0 10, 10, 5, 5} Answer link If you subtract one side of the equation from the other, so the solutions are at 0, you can use outer to calculate a grid of z values, which contour can then plot x < seq (2, 2, by = 001) # high granularity for good resolution z < outer (x, x, FUN = function (x, y) x^2*y^3 (x^2y^21)^3) # specify level to limit contour lines printed

Plot x : 1 x : 2

Plot x : 1 x : 2- Probably you can recognize it as the equation of a circle with radius r = 1 and center at the origin, (0,0) The general equation of the circle of radius r and center at (h,k) is (x −h)2 (y −k)2 = r2 Answer link MATLAB is a casesensitive language (that upper and lower case matters), so you must use uppercase "X" consistently, and "plot" is all lower case The "^" (raise to the power) operator is for square matrices To computer a perelement raise to the power, use "^" instead X=0013 Y=2^X plot (X,Y)

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X 2 y 2 − 1 = x 2 / 3 y , which can easily be solved for y y = 1 2 ( x 2 / 3 ± x 4 / 3 4 ( 1 − x 2)) Now plot this, taking both branches of the square root into account You might have to numerically solve the equation x 4 / 3 4 ( 1 − x 2) = 0 in order to get the exact x interval ShareIt depends a bit on what you are plotting If you use Plot then, as expected both functions give standard "vertical" parabolas When you try to plot x=y^2 like that that would just be renaming the variables If however you use ContourPlot ContourPlot {y == x^2, x == y^2}, {x, 2, 2}, {y, 2, 2} you get which appears to be what you wantX2 2 34 Matrix Plot of Y, X1, X2 (b) Regression Analysis Y versus X1, X2 The regression equation is Y = 377 442 X1 438 X2 Predictor Coef SE Coef T P Constant 2996 1257 0000 X1 1470 0000 X2 650

 If you want to plot line segments between points, I guess you could sort the data by x For this particular example I would be tempted to use an ad hoc method x^2y^2xyxy=0 can be rewritten as 3/4x^21/2x (y1/2x)^2 (y1/2x)=0 Define u=y1/2x then 3/4x^21/2 x% this is yaxis Now, my question is what I should do if I want to have a plot with 2 xaxes, both at the bottom but representing the same for both x1 and x2 Say, at x1 = 006, I want x2 = 9 from X axis 2 to be directly under the value x1 I also want each value of x1 and x2 to be exactly the same upper and lower postion ofFind where the curve passes the x axis Here we get 0=x 21 So x 2 =1 The square roots of 1 are 1 and 1 (1x1=1, 1x1=1) This means the curve crosses the x axis as (1, 0) and (1,0) Remember the order of this equation (the highest power to which a x is raised) gives the number of times the curve crosses the x axis, here it is

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Sets the step inbetween ticks on this axis Use with `tick0` Must be a positive number, or special strings available to "log" and "date" axes If the axis `type` is "log", then ticks are set every 10^ (n"dtick) where n is the tick number For example, to set aGraph y=x^21 y = x2 − 1 y = x 2 1 Find the properties of the given parabola Tap for more steps Rewrite the equation in vertex form Tap for more steps Complete the square for x 2 − 1 x 2 1 Tap for more steps Use the form a x 2 b x c

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